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Matemáticas

Histograms

Frequency density is frequency divided by class width, and area represents frequency. Why histograms differ from bar charts and how to read one backwards.

La respuesta corta

A histogram displays continuous data with no gaps between bars. When class widths are unequal the vertical axis shows frequency density, which is frequency divided by class width, so that the area of each bar rather than its height represents the frequency.

El método, paso a paso

  1. Calculate the class width

    class 10 < x ≤ 30 → width 20

    Upper bound minus lower bound. Getting this wrong makes every subsequent figure wrong, and classes are often written in ways that make the width easy to misread — particularly when bounds are decimals.

  2. Divide frequency by class width

    frequency 30, width 20 → frequency density 1.5

    Frequency density is what goes on the vertical axis. It answers 'how crowded is this class', which is what makes classes of different widths comparable at a glance.

  3. Draw bars with no gaps

    each bar spans its class, touching its neighbours

    The data is continuous, so the classes meet rather than sitting apart. A gap would imply values that cannot occur, which is why histograms and bar charts are drawn differently.

  4. Area equals frequency

    width 20 × density 1.5 = frequency 30

    This is the defining property. To find a frequency from a histogram you compute the area of the bar, not read its height — reading heights as frequencies is the error the entire topic is designed to expose.

  5. Work backwards for part of a class

    half a class of width 20 → 10 × 1.5 = 15

    Questions frequently ask for the frequency in a range that cuts across a class. Assuming the data is evenly spread within the class, take the proportion of the width you need and multiply by the density.

Why height alone would mislead

If one class spans 10 units and another spans 50, plotting raw frequency as height makes the wide class look the same as the narrow one even though it covers five times as much ground. The eye compares areas, so unequal widths with equal heights create a false impression.

Frequency density corrects this by measuring how concentrated the data is per unit, which is why area then represents frequency honestly. It is a fix for a genuine visual problem rather than an arbitrary complication.

  • Frequency density = frequency ÷ class width
  • Area of bar = frequency
  • No gaps — the data is continuous
  • Read frequencies as areas, never heights
  • Part of a class → that proportion of the width × density

Not a bar chart

A bar chart shows discrete categories with gaps and heights that represent frequency directly. A histogram shows continuous data with no gaps and, when widths differ, areas that represent frequency. They look similar and behave differently.

The most reliable tell is the horizontal axis: categories mean bar chart, a continuous numerical scale means histogram. Once that is settled, whether to read heights or areas follows.

When all the classes are the same width

With equal class widths, frequency density is just frequency divided by a constant, so the bars have the same relative heights either way and the axis can be labelled frequency without misleading anyone.

This is why some early textbooks show histograms with frequency on the vertical axis. It is a special case rather than the general rule, and exam questions overwhelmingly use unequal widths precisely because that is where the understanding shows.

How we teach histograms

We build the frequency density column as an explicit step in every table, even when the widths are equal. It keeps the habit intact for the questions where widths differ, which are the ones that carry the marks.

We also give the backwards questions — frequency from an area, or a partial class — equal time with the drawing. Students are generally competent at producing a histogram and much weaker at extracting information from one, which is what examiners actually ask.

Preguntas frecuentes

What is frequency density?

Frequency divided by class width. It goes on the vertical axis of a histogram so that classes of different widths can be compared fairly, and it makes the area of each bar equal to its frequency.

What is the difference between a histogram and a bar chart?

A bar chart shows discrete categories with gaps and heights representing frequency. A histogram shows continuous data with no gaps, and when class widths differ it is the area, not the height, that represents frequency.

How do you find frequency from a histogram?

Multiply the bar's width by its height — the area is the frequency. Reading the height alone gives frequency density, not frequency, and that is the error histogram questions are designed to catch.

Why do histograms have no gaps between bars?

Because the data is continuous, so each class meets the next. A gap would suggest values that cannot occur. Bar charts have gaps precisely because their categories are separate and discrete.

How do you find the frequency for part of a class?

Assume the data is spread evenly within the class, then take the proportion of the width you need and multiply by the frequency density. Half of a class of width 20 with density 1.5 gives 10 × 1.5 = 15.

Fuentes

  1. AQA GCSE Mathematics 8300 specificationAQA
  2. 3.1 Terminology — Introductory Statistics 2eOpenStax, Rice University

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